if ionisation constant of an acid HA at equilibrium is 1.0 * 10^ 8, then calculate the value of pKa and pKb (for its conjugate base )
![SOLVED: cc 1. If the Ka of the conjugate acid is 5.14 × 10-7 , what is the pKb for the base? 2. The Kb of dimethylamine [(CH3)2NH] is 5.90x10–4 at 25°C. SOLVED: cc 1. If the Ka of the conjugate acid is 5.14 × 10-7 , what is the pKb for the base? 2. The Kb of dimethylamine [(CH3)2NH] is 5.90x10–4 at 25°C.](https://cdn.numerade.com/ask_previews/65f8ab16-8ad2-4bf2-8167-db27117be525_large.jpg)
SOLVED: cc 1. If the Ka of the conjugate acid is 5.14 × 10-7 , what is the pKb for the base? 2. The Kb of dimethylamine [(CH3)2NH] is 5.90x10–4 at 25°C.
![pH, pOH, H3O+, OH-, Kw, Ka, Kb, pKa, and pKb Basic Calculations -Acids and Bases Chemistry Problems - YouTube pH, pOH, H3O+, OH-, Kw, Ka, Kb, pKa, and pKb Basic Calculations -Acids and Bases Chemistry Problems - YouTube](https://i.ytimg.com/vi/OEW4-Sfyvik/maxresdefault.jpg)